DataFlex Studio Search regex tips: Difference between revisions
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Created page with "'' Tips from Marco '' The DataFlex Studio has the possibility to use regular expressions in the Find dialog. This opens the possibility to search for very specific things. ==== Find <xx> Table ==== Useful is <source lang="dataflex"> find .. Customer </source> where the . is any character, so eq gt ge etc. If you also have and would like to find any number of spaces then you can extend it by \s for a space character followed by one or more with a + <source lang=..." |
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==== Looking for a function that | ==== Looking for a function that has a number as the parameter ==== | ||
<source lang="dataflex"> | <source lang="dataflex"> | ||
| Line 43: | Line 43: | ||
"returns" | "returns" | ||
==== Find old subroutines ==== | |||
<source lang="dataflex"> | |||
^\w+: | |||
</source> | |||
^ is start at character 1 on the line | |||
\w is a word character | |||
+ is one of more of the previous | |||
: is exactly that, a ':' | |||
So this finds | |||
<source lang="dataflex"> | |||
Start: | |||
Start_A: | |||
Start_5: | |||
</source> | |||
But not if there is a space before the word or a space between the word character and the : | |||
[[Category: Studio]] | [[Category: Studio]] | ||
Latest revision as of 11:57, 31 January 2022
Tips from Marco
The DataFlex Studio has the possibility to use regular expressions in the Find dialog.
This opens the possibility to search for very specific things.
Find <xx> Table
Useful is
find .. Customer
where the . is any character, so eq gt ge etc.
If you also have and would like to find any number of spaces then you can extend it by \s for a space character followed by one or more with a +
find\s+..\s+customer
Looking for a function that has a number as the parameter
function .* number .* returns
Basically, the . is any character and the * is any occurrence of the previous character. So it is matching:
"function" space any characters "number" space any characters space "returns"
Find old subroutines
^\w+:
^ is start at character 1 on the line \w is a word character + is one of more of the previous : is exactly that, a ':'
So this finds
Start: Start_A: Start_5:
But not if there is a space before the word or a space between the word character and the :
